I agree with your logic to the poster above you about not being able to have 9 pitches but, your answer is also wrong.
rwilymz » Wed Feb 28 2007 posted
What's the fewest number of pitches possible in a 9-inning complete game?
He did not say for one team's pitches but, a 9-inning complete game.
I am not sure about the interference rule but, if that is true and by your logic to his statement (Which makes more sense than his logic.) the answer would be 35. The first 8 innings the first batter of each team gets a triple, tries to steal home, is thrown out as is the batter for interference and the third batter flies out or gets thrown out. The ninth inning the away team's first batter gets a triple, tries to steal home, is thrown out as is the batter for interference and the third batter flies out or gets thrown out, the first batter of the home team gets a home run on the first pitch.
The answer is 35. (4X8=32 32+2+1+35) Final score 0-1
For the first 8 innings if, the interference rule is not true, this is how it would play out, both teams on the first pitch for each batter would have to fly out or get thrown out. The ninth inning the away team would have 3 fly outs or thrown outs on each of their first at bats and the home team's first at bat in the ninth inning would be a home run.
The answer is 52 (6X8=48 48+3+1=52) Final score 0-1
The answer for just the away team would be 18 or 27 depending on which logic you use and the away team would have to score at least one run.
Final score 1 or more-0
The answer for just the home team would be 16 or 24 depending on which logic you use and the home team would have to score at least one run in the first 8 innings, they would not have to pitch in the ninth inning.
Final score 0-1 or more
I am a smarta$$, that is better than being a dumba$$
I have twin boys, Pete and Repete
reply
share